Question

Let PS be the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3). The equation of the line passing through (1, -1) and parallel to PS is

• A. 2x – 9y – 7 = 0
• B. 2x – 9y – 11 = 0
• C. 2x + 9y – 7 = 0
• D. 2x – 9y + 7 = 0

Answer 1

The correct option is D 2x – 9y + 7 = 0

S = midpoint of QR = $(\frac{6+7}{2},\frac{-1+3}{2})=(\frac{13}{2},1)\therefore \text{slope of}PS=\frac{2-1}{2-\frac{13}{2}}=-\frac{2}{9}\therefore \text{The required equation is}y+1=\frac{-2}{9}(x-1)i.e.,2x+9y+7=0$