Let PS be the median of the triangle with vertices P(2,2),Q(6,−1)andR(7,3). The equation of the line passing through (1,−1) and parallel to PS is
A
4x−7y−11=0
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B
2x+9y+7=0
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C
4x+7y+3=0
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D
2x−9y−11=0
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Solution
The correct option is B2x+9y+7=0 S is the mid point of line QR
∴ The coordinates of S are (132,1)
the slope of median PS, m=1−2132−2=−29
The equation of the line passing through point (1,−1) and having slope −29 is y+1=−29(x−1) ⇒2x+9y+7=0