Question

Let PS, be the median of the triangle with vertices P(2,2), Q(6,-1) and R(7,3) . Find the equation of line passing through (-1,1) and parallel to PS.

Answer 1

We have given PS is he median of $\Delta PQR.$ Since , S is the mid point of Q and R.

$\therefore$ Coordinates of $S=(\frac{6+7}{2},\frac{-1+3}{2})=(\frac{13}{2},1)$

Now , slope of PS,$m=\frac{2-1}{2-\frac{13}{2}}=-\frac{2}{9}$

Now equation of line passing through (-1,-1)and parallel to PS is

$y+1=-\frac{2}{9}(x+1)$

$\Rightarrow 9y+9=-2x-2$

$\therefore 2x+9y+11=0$