Question

Let $PS$ be the median of triangle with vertices $P(2,2),Q(6,-1)$ and $R(7,3)$. The equation of line passing through $(1,-1)$ and parallel to $PS$ is

• A. $2x-9y-7=0$
• B. $2x-9y-11=0$
• C. $2x+9y-11=0$
• D. $2x+9y+7=0$

Answer 1

The correct option is D $2x+9y+7=0$

$\because S$ is the mid point of $QR$
$\therefore S\equiv (\frac{13}{2},1)$
Now slope of $PS=\frac{2-1}{2-\frac{13}{2}}=-\frac{2}{9}$
$\therefore$ required line : $(y+1)=-\frac{2}{9}(x-1)$
$\Rightarrow 2x+9y+7=0$