The correct option is C Not symmetric
Let R={(1,3),(4,2),(2,4),(2,3),(3,1)} be a relation on the set A={1,2,3,4}, then
(a) Since (2,4) ∈ R and (2,3) ∈ R, so R is not a function.
(b) Since (1,3) ∈ R and (3,1) ∉ R but (1,1) ∉ R, so R is not transitive:
(c) Since (2,3) ∈ R but (3,2) ∉ ′R, so R is not symmetric.
(d) Since (1,1) ∉ R, so R is not reflexive.
Hence, option C is correct.