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Standard XII

Mathematics

Centroid of a Triangle

Let r and ...

Question

Let $r$ and $r^{'}$ denote the angle inside an equilateral prism, as usual, in degrees. Consider that during some time interval from $t = 0$ to $t, r^{'}$ varies with time as $r^{'} = 10 + t^{2}$ . During this time, $r$ will vary as (assume that $r$ and $r^{'}$ are in degree).

50 - t^{2}

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50 + t^{2}

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60 - t^{2}

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60 + t^{2}

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Solution

The correct option is D $50 - t^{2}$
$r + r^{^{'}} = A = 60$
$r = 60 - r^{^{'}} = 60 - (10 + t^{2}) = 50 - t^{2}$
option $A$ is correct

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Let r and r′ denote the angle inside an equilateral prism, as usual, in degrees. Consider that during some time interval from t=0 to t,r′ varies with time as r′=10+t2. During this time, r will vary as (assume that r and r′ are in degree).

The correct option is D 50−t2r+r′=A=60r=60−r′=60−(10+t2)=50−t2option A is correct

Let $r$ and $r^{'}$ denote the angle inside an equilateral prism, as usual, in degrees. Consider that during some time interval from $t = 0$ to $t, r^{'}$ varies with time as $r^{'} = 10 + t^{2}$ . During this time, $r$ will vary as (assume that $r$ and $r^{'}$ are in degree).

The correct option is D $50 - t^{2}$
$r + r^{^{'}} = A = 60$
$r = 60 - r^{^{'}} = 60 - (10 + t^{2}) = 50 - t^{2}$
option $A$ is correct