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Byju's Answer
Standard IX
Mathematics
Transitive Relations
Let R and ...
Question
Let
R
and
S
be two non-void relation on a set A. Which of the following statement is false
A
R
and
S
are transitive
⇒
R
∪
S
is transitive
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B
R
and
S
are transitive
⇒
R
∩
S
is transitive
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C
R
and
S
are symmetric
⇒
R
∪
S
is symmetric
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D
R
and
S
are reflexive
⇒
R
∩
S
is reflexive.
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Solution
The correct option is
A
R
and
S
are transitive
⇒
R
∪
S
is transitive
Let
A
=
{
1
,
2
,
3
}
Let the two transitive relations on set
A
be
R
=
{
(
1
,
1
)
,
(
1
,
2
)
}
and
S
=
{
(
2
,
2
)
,
(
2
,
3
)
}
Now,
R
∪
S
=
{
(
1
,
1
)
,
(
1
,
2
)
,
(
2
,
2
)
,
(
2
,
3
)
}
Hence,
(
1
,
2
)
,
(
2
,
3
)
∈
R
∪
S
⇒
(
1
,
3
)
∈
R
∪
S
∴
R
∪
S
is not transitive.
Suggest Corrections
0
Similar questions
Q.
On set
A
=
{
1
,
2
,
3
}
, relations
R
and
S
are given by
R
=
{
(
1
,
1
)
,
(
2
,
2
)
,
(
3
,
3
)
,
(
1
,
2
)
,
(
2
,
1
)
}
S
=
{
(
1
,
1
)
,
(
2
,
2
)
,
(
3
,
3
)
,
(
1
,
3
)
,
(
3
,
1
)
}
. Then
Q.
Let
A
=
{
1
,
2
,
3
}
and
R
,
S
be two relations on
A
given by
R
=
{
(
1
,
1
)
,
(
2
,
2
)
,
(
3
,
3
)
,
(
1
,
2
)
,
(
2
,
1
)
}
,
S
=
{
(
1
,
1
)
,
(
2
,
2
)
,
(
3
,
3
)
,
(
2
,
3
)
,
(
3
,
2
)
}
then
R
∪
S
is
Q.
If R and S are relations on a set A, then prove that
(i) R and S are symmetric ⇒ R ∩ S and R ∪ S are symmetric
(ii) R is reflexive and S is any relation ⇒ R ∪ S is reflexive.
Q.
Let R be the relation in the set {1, 2, 3, 4} given by R = {(1, 2), (2, 2), (1, 1), (4, 4), (1, 3), (3, 3), (3, 2)}. Choose the correct answer. (A) R is reflexive and symmetric but not transitive. (B) R is reflexive and transitive but not symmetric. (C) R is symmetric and transitive but not reflexive. (D) R is an equivalence relation.
Q.
Let R be the relation on the set A = {1, 2, 3, 4} given by
R = {(1, 2), (2, 2), (1, 1), (4, 4), (1, 3), (3, 3), (3, 2)}. Then,
(a) R is reflexive and symmetric but not transitive
(b) R is reflexive and transitive but not symmetric
(c) R is symmetric and transitive but not reflexive
(d) R is an equivalence relation
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