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Question

Let R be a relation defined as aRb if |a|b. Then, the relation R is

A
reflexive
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B
symmetric
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C
transitive
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D
None of these
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Solution

The correct option is C transitive
R is not reflexive, if a is any negative real number, then |a|>a so that a is not in Ra.

R is not symmetric.

Consider the real numbers a=2 and b=3.

Then, aRb as |2|<3.

But b not in Ra as |3|2.

R is transitive: let a,b,c be three real numbers such that |a|b and |b|c.

But |a|bb0, and so |b|cbc.

So, it follows |a|c.

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