Let $R$ be a relation defined by $R = {(9, 8), (1, 9), (9, 6), (7, 6), (2, 7)}$ then $R^{- 1}$ is given by

{(8, 9), (9, 1), (6, 9), (6, 7), (7, 2)}

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{(1, 1), (9, 9), (7, 9), (9, 7), (7, 7)}

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{(1, 8), (1, 6), (2, 6)}

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None of these

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Solution

The correct option is D ${(8, 9), (9, 1), (6, 9), (6, 7), (7, 2)}$
Given $R = {(9, 8), (1, 9), (9, 6), (7, 6), (2, 7)}$
$∴ R^{- 1} = {(8, 9), (9, 1), (6, 9), (6, 7), (7, 2)}$
Ans: A

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