Given: R={(a,b):a,b∈N and a=b2}
If (a,b)∈R, then
a=b2 ...(1)
And (b,c)∈R
b=c2 ...(2)
From (1) and (2), we get
a=c4 ...(3)
If (a,c)∈R, then
a=c2
From equation (3), we get
c2=c4
⇒c2(c2−1)=0
⇒c=0,±1
As relation is defined from N to N, so c=1
So, (a,b)∈R and (b,c)∈R doesn't imply that (a,c)∈R
Hence, the given statement is False.