Let R be a relation in N defined by x- y - R - x-2 y-8- Express R and R -1 as sets of ordered pairs-

Let R be a relation in N defined by (x, y) isin; R hArr; x + 2y = 8. We have: x = 8 2y For y = 3, 2, 1, we have: x = 2, 4, 6 there4; nbsp;R = (2, 3), ...

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Standard XII

Mathematics

Asymptotes

Let R be a re...

Question

Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y =8. Express R and R⁻¹ as sets of ordered pairs.

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Solution

Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y = 8.
We have:
x = 8 $-$ 2y
For y = 3, 2, 1, we have:
x = 2, 4, 6
∴ R = {(2, 3), (4, 2), (6, 1)}
And,
R⁻¹= {(3, 2), (2, 4), (1, 6)}

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Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y =8. Express R and R−1 as sets of ordered pairs.

Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y = 8. We have: x = 8-2y For y = 3, 2, 1, we have: x = 2, 4, 6 ∴ R = {(2, 3), (4, 2), (6, 1)} And, R−1 = {(3, 2), (2, 4), (1, 6)}

Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y =8. Express R and R⁻¹ as sets of ordered pairs.

Let R be a relation in N defined by (x, y) ∈ R ⇔ x + 2y = 8.
We have:
x = 8 $-$ 2y
For y = 3, 2, 1, we have:
x = 2, 4, 6
∴ R = {(2, 3), (4, 2), (6, 1)}
And,
R⁻¹= {(3, 2), (2, 4), (1, 6)}