The correct option is C reflexive and transitive only
Let n∈N,∴ n is a factor of n
∴nRn.∴ R is reflexive
3R6 because 3 is a factor of 6.
Also 6 is not a factor of 3.
∴(6,3)/∈R.∴R is not symmetric.
Let aRb and bRc.
∴b=ak1 and c=bk2 for k1,k2∈N.
∴c=(ak1)k2=a(k1k2) or a is a factor of c.
∴aRc,∴ R is transitive.
∴ The correct answer is C