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Question

Let R be a relation on N×N defined by (a,b)R,(c,d)a+d=b+c for all (a,b),(c,d)ϵN×N

Show that :

(i) (a, b) R (a, b) for all (a,b)ϵN×N

(ii) (a,b)R(c,d)(c,d)R(a,b) for all (a,b),(c,d)ϵN×N

(iii) (a, b) R (c, d) and (c, d) R (e, f) (a, b) R (e, f) for all (a, b), (c, d), (e, f) ϵN×N.

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Solution

We have,

(a,b)R,(c,d)a+d=b+c for all (a,b),(c,d)ϵN×N

(i) We have,

a + b = b + a for all a,bϵN

(a,b)R(a,b) for all, a,bϵN

(ii) Now,

(a, b) R (c, d)

a+d=b+c

c+d=d+a

(c,d)R(a,b)

(iii) Now,

(a, b) R (c, d) and (c, d) R (e, f)

a+d=b+c and c + f = d + e

a+d+c+f=b+c+d+e (Adding)

a+f=b+e

(a,b)R(e,f)


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