Let R be a relation on the set N be defined by {(x,y)|x,y|N,2x+y=41}. Then R is
None of these
On the set N of natural numbers,
R = {(x,y): x,y ∈ N , 2x + y = 41}.
Since (1,1) ∉ R as 2.1+1 = 3 ≠ 41. So R is not reflexive.
(1,39) ∈ R But (39,1) ∉ R . So R is not symmetric, (20,1)
(1,39) ∈ R . But (20,39) ∉ R. So R is not transitive .