Let R be a relation on the set N given by
R = {(a, b) : a = b − 2, b > 6}. Then,
(a) (2, 4) ∈ R
(b) (3, 8) ∈ R
(c) (6, 8) ∈ R
(d) (8, 7) ∈ R

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Solution

(c) (6, 8) ∈ R

$(6, 8) \in R Then, a = b - 2 \Rightarrow 6 = 8 - 2 and b = 8 > 6 Henc e, (6, 8) \in R$

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Similar questions

Q. Let R be the relation in the set N given by R = {( a , b ): a = b − 2, b > 6}. Choose the correct answer. (A) (2, 4) ∈ R (B) (3, 8) ∈R (C) (6, 8) ∈R (D) (8, 7) ∈ R

Let R be the relation in the set N given by R = {(a, b): a = b − 2, b > 6}. Choose the correct answer.

(A) (2, 4) ∈ R (B) (3, 8) ∈R (C) (6, 8) ∈R (D) (8, 7) ∈ R

Q. Let

R

be a relation on the set

N

given by

R = {(a, b) : a = b - 2, b > 6}

. Then

Let R be the relation in the set N given by R = {(a, b): a = b - 2, b > 6}. Choose the correct answer.
$(A) (2, 4) \in R (B) (3, 8) \in R (C) (6, 8) \in R (D) (8, 7) \in R$

Q. Let

R

be the relation in the set

N

given by

R = {(a, b) : a = b - 2, b > 6}

. Choose the correct answer.

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Let R be a relation on the set N given by R = {(a, b) : a = b − 2, b > 6}. Then, (a) (2, 4) ∈ R (b) (3, 8) ∈ R (c) (6, 8) ∈ R (d) (8, 7) ∈ R

(c) (6, 8) ∈ R 6, 8∈R Then, a=b-2⇒6=8-2and b=8 > 6Hence, 6, 8∈R

Let R be a relation on the set N given by
R = {(a, b) : a = b − 2, b > 6}. Then,
(a) (2, 4) ∈ R
(b) (3, 8) ∈ R
(c) (6, 8) ∈ R
(d) (8, 7) ∈ R

(c) (6, 8) ∈ R

$(6, 8) \in R Then, a = b - 2 \Rightarrow 6 = 8 - 2 and b = 8 > 6 Henc e, (6, 8) \in R$