The correct option is C Not reflexive but symmetric
R={(p,q),(r,s)|p−s=q−r}
(i) Check reflexive property
∀(p,q)ϵZ+×Z+ ((p,q),(p,q))ϵR
is true iff p−q=q−p which is false.
So relation R is not reflexive.
(ii) Check symmetry property
If ((p,q),(r,s))ϵR then ((r,s),(p,q))ϵR
((p,q),(r,s))ϵR⇒p−s=q−r
((r,s),(p,q))ϵR⇒r−q=s−p
If p−s=q−r is true, then r−q=s−p is also true by rearranging the equation.
∴R is symmetric.