Given: R is the equivalence relation on the set Z of integers defined as (x, y) ∈ R ⇔ x − y is divisible by 2.
To find the equivalence class [1], we put y = 1 in the given relation and find all the possible values of x.
Thus,
R = {(x, 1): x − 1 is divisible by 2}
⇒ x − 1 is divisible by 2
⇒ x = ±1, ±3, ±6, ±9, ....
Therefore, equivalence class [0] = {±1, ±3, ±6, ±9, ....}
Hence, the equivalence class [1] is {±1, ±3, ±6, ±9, ....}.