The correct option is D An equivalence relation
We have (a,b)R(a,b) for all (a,b)∈N×N
Since a+b=b+a. hence, R is reflexive.
R is symmetric for we have (a,b)R(c,d)⇒a+d=b+c
⇒d+a=b+c⇒c+b=d+a⇒(c,d)R(a,b)
Hence R is symmetric
Then by definition of R, we have
a+d=b+c and c+f=d+e
Hence by addition, we get
a+d+c+f=b+c+d+e or a+f=b+e
Hence (a,b)R(e,f)
Thus (a,b)R(c,d) and (c,d)R(e,f)⇒(a,b)R(e,f)
Hence R is transitive.