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Question

Let r be a root of the equation x2+ 2x + 6 = 0. The value of (r + 2) (r + 3) (r + 4) (r + 5) is equal to.


A

51

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B

-51

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C

-126

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D

126

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Solution

The correct option is C

-126


r be a root r2 + 2r + 6 = 0 ...................(1)

now (r+2) (r+3) (r+4) (r+5)

= (r2 + 5r +6) (r2+ 9r + 20)

= (3r) (7r + 14) using (i)

= 21 (r2+ 2r)

= -126 using (i)


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