Let R be the relation over the set of all straight lines in a plane such that
l1Rl2⇔l1⊥l2. Then, R is
Symmetric
Clearly R is not a reflexive relation, because a line cannot be perpendicular to itself.
Let l1Rl2, Then
l1Rl2⇒l1⊥l2
⇒l2⊥l1
⇒l2Rl1
∴ R is a symmetric relation.
R is not a transitive relation, because if
l1⊥l2 And l2⊥l1, then l1 may be parallel to l2