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Question

Let R be the relation over the set of integers such that mRn if and only if m is a multiple of n.Then R is

A
reflexive
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B
symmetric
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C
transitive
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D
an equivalence relation
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Solution

The correct options are
A reflexive
D transitive
We know that a number is a factor as well as multiple of itself.
Since 'n' will be a factor of 'n' for any natural number, hence (n,n) will be a subset of the relation. In other words nRn for a natural number 'n' holds true. This makes the relation reflexive.
If 'n' is a factor of 'm' then simultaneously 'm' cannot be a factor of 'n' since nm.
Thus mRnnRm is not true. Thus the relation is not symmetric.
Now, if 'm' is multiple of 'n' and 'p' be a multiple of 'm', (all being distinct natural numbers), then 'n' will be a common factor of 'm' and 'p'. Thus
pRmmRnpRn is true.
Hence the relation is transitive.

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