Let R be the relation over the set of straight lines of a plane, such that l1Rl2⇔l1±l2 . Then, R is
A
symmetric
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B
reflexive
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C
transitive
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D
an equivalence relation
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Solution
The correct option is Asymmetric l1Rl1⇒l1 is not perpendicular to l1
(∴ R is not reflexive) l1Rl2⇒l1±l2 ⇒l2Rl1⇒l2Rl1 , Hence, R is symmetric. l1Rl2 and l2Rl3/⇒l1Rl3 .(∴ R is not transitive)