Relation between Roots and Coefficients for Higher Order Equations
Let r, s, t a...
Question
Let r,s,t and u be the roots of the equation x4+Ax3+Bx2+Cx+D=0; A,B,C,D∈R. If rs=tu, then A2D is equal to
A
BC
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B
B2
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C
0
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D
C2
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Solution
The correct option is DC2 Since, r,s,t and u are roots of the equation x4+Ax3+Bx2+Cx+D=0
We know that, r+s+t+u=−A⋯(1) (r+s)(t+u)+rs+tu=B⋯(2) rs(t+u)+tu(r+s)=−C⋯(3) rstu=D⋯(4)⇒(rs)2=D⋯(5) [∵rs=tu]
Using equation (3), rs(r+s+t+u)=−C
Using equation (1), ⇒rs=CA
Using equation (5), ⇒C2A2=D⇒A2D=C2