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Question

Let remainder when p(x) is divided by q(x) using remainder theorem is A. p(x)=x95x4+1,q(x)=x+1
Find the value of A+10.

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Solution

p(x)=x95x4+1 and
g(x)=x+1
=>x+1=0
=>x=1
The remainder when p(x) is divided by g(x) is p(1) (By Remainder Theorem)
Thus,
p(1)=(1)95(1)4+1
=15+1
=5

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