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Question

Let [ ] represents the greatest integer function and [x3+x2+1+x]=[x3+x2+1]+x. The number of solution(s) of the equation in |[x]|=2−|[x]| is

A
1
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B
Zero
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C
3
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D
2
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Solution

The correct option is B 2
Given that,
[x3+x2+1+x]=[x3+x2+1]+x

Possible when x3+x2+1 and x are in sequence .
no. of solution of the equation.

|[x]|=2|[x]|2|[x]|=2|[x]|=1[x]=±1[x]=1[x]=1

Therefore,
Number of solution =2

Hence, this is the answer.

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