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Question

Let S be set of all rational numbers. The functions f:RR, g:RR are defined as
f(x)={0,xS1,xS
g(x)={1xS0xS
then, (fog)(π)+(gof)(e)=

A
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B
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C
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D
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Solution

The correct option is C 1
f(x)={0,x is rational1,x is irrational
g(x)={1x is rational0x is irrational
fog(π)=f(g(π))=f(0)=0
so gof(e)=g(f(e))=g(1)=1
fog(π)+gof(e)=1

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