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Question

Let S be the circle in the xy-plane defined by the equation x2+y2=4. Let E1E2 and F1F2 be the chord of S passing through the point Po(1, and parallel to the x-axis and the y-axis, respectively. Let G1G2 be the chord of S passing through Po and having slop-1. Let the tangents to S at E1 and E2 meet at E3, the tangents of S at F1 and F2 meet at F3, and the tangents to S at G1 and G2 meet at G3. Then, the points E3, F3 and G3 lie on the curve.

A
x+y=4
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B
(x4)2+(y4)2=16
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C
(x4)(y4)=4
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D
xy=4
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Solution

The correct option is D x+y=4
Co-ordinates of E1 and E2 are obtained by solving y=1 and x2+y2=4
E1(3,1) and E2(3,1)
co-ordinates of F1 and F2 are obtained by solving
x=1 and x2+y2=4
F1(1,3) and F2(1,3)
Tangent at E1:3x+y=4
Tangent at E2:3x+y=4
E3(0,4)
Tangent at F1:x+3y=4
Tangent at F2:x3y=4
F3(4,0)
and similarly G3(2,2)
(0,4),(4,0) and (2,2) lies on x+y=4
828424_903797_ans_4953b966228b48eaac1dc2dded52462a.png

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