The correct option is D The center of S is (1,2)
The circle having center at the radical center of the three given circles and radius equal to the length of the tangent from it to any one of the three circles cuts all the three circles orthogonally. The given circles are
x2+y2−3x−6y+14=0, ....(1)x2+y2−x−4y+8=0, ....(2)x2+y2+2x−6y+9=0 ....(3)
The radical axes of (1),(2) and (3) are, respectively.
x+y−3=0 .....(4)3x−2y+1=0 .....(5)
Solving (4) and (5), we get x=1,y=2
Thus, the coordinates of the radical center are (1,2). The length of the tangent from (1,2) to (1) is
r=√1+4−3−12+14=2
Hence, the equation of the required circle is
(x−1)2+(y−2)2=22⇒x2+y2−2x−4y+1=0