The correct option is B S is the empty set
Given:
x2–y2=12345678⇒(x+y)(x−y)=12345678
As x and y are positive integers.
x+y will be positive, so x−y should be positive.
As the RHS is even number, so one of them should be even.
If (x+y) is even then (x−y) wil also be even and vice-versa.
Therefore both (x+y) and (x−y) are even.
So (x+y)(x−y) will be divisible by 4, but RHS is not divisible by 4.
Hence there does not exist any pair of (x,y).
Hence, The correct answer is option B.