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Question

Let S be the set of all real roots of the equation, 3x(3x1)+2=|3x1|+|3x2|. Then S :

A
is a singleton.
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B
is an empty set.
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C
contains at least four elements.
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D
contains exactly two elements.
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Solution

The correct option is A is a singleton.
3x(3x1)+2=|3x1|+|3x2|
Let 3x=t
Then t(t1)+2=|t1|+|t2|
t2t+2=|t1|+|t2|
We plot t2t+2 and |t1|+|t2|
As t=3x is always positive, therefore only positive values of t will be the solution.


The graphs intersect for only positive value of t.
So, there is single value of x given by x=log3t
Therefore, we have only one solution.

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