CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let S be the set of all real roots of the equation, 3x(3x1)+2=|3x1|+|3x2|. Then S :

A
is an empty set.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
contains at least four elements.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
is a singleton.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
contains exactly two elements.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C is a singleton.
3x(3x1)+2=|3x1|+|3x2|

Let 3x=t

Then t(t1)+2=|t1|+|t2|
t2t+2=|t1|+|t2|

We plot t2t+2 and |t1|+|t2|
As t=3x is always positive, therefore only positive values of t will be the solution.



The graphs intersect for only positive value of t.

So, there is single value of x given by x=log3t

Therefore, we have only one solution.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphs of Quadratic Equation for different values of D when a>0
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon