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Byju's Answer
Standard XII
Mathematics
Graph of Quadratic Expression
Let S be the ...
Question
Let
S
be the set of all real roots of the equation,
3
x
(
3
x
−
1
)
+
2
=
|
3
x
−
1
|
+
|
3
x
−
2
|
. Then
S
:
A
is a singleton.
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B
is an empty set.
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C
contains at least four elements.
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D
contains exactly two elements.
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Solution
The correct option is
A
is a singleton.
3
x
(
3
x
−
1
)
+
2
=
|
3
x
−
1
|
+
|
3
x
−
2
|
Let
3
x
=
t
Then
t
(
t
−
1
)
+
2
=
|
t
−
1
|
+
|
t
−
2
|
⇒
t
2
−
t
+
2
=
|
t
−
1
|
+
|
t
−
2
|
We plot
t
2
−
t
+
2
and
|
t
−
1
|
+
|
t
−
2
|
As
t
=
3
x
is always positive, therefore only positive values of
t
will be the solution.
The graphs intersect for only positive value of
t
.
So, there is single value of
x
given by
x
=
log
3
t
Therefore, we have only one solution.
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