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Question

Let S be the set of all values of x such that log2x(x2+5x+6)<1 then the sum of all integral value of x in the set S, is

A
0
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B
8
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C
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D
10
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Solution

The correct option is D 0
log2x(x2+5x+6)<1

x2+5x+6<2x1

x2+3x+6<0

But x2+3x+6=0 has no real roots

S is an empty set

sum of all integral values of x=0

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