Let S be the set of integers. For a,b∈S,aRb if and only if |a−b|<1,then
A
R is not a reflexive relation
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
R is not a symmetric relation
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R is an equivalence relation
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
R is not an equivalence relation
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is DR is an equivalence relation Relation : aRb Here (a,a)∈R,(a−a)=0<1 So it is reflexive. Also (a,b)∈R the (b,a)∈R∣a−b∣<1 So it is symmetric also.
Also as S is a set of integers, for the relation to be present, a should be equal to b.
∴aRb is transistive ⇒aRb is an equivalence relation.