wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let S be the set of values of 'a' for which 2 lie between the roots of quadratic equation x2+(a+2)x(a+3)=0. Then S is given by

A
(,5)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(5,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(,5]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[5,)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (,5)
Solution : x2+(a+2)x(a+3)=0
f(2)<0
4+2(a+2)(a+3)<0
a+5<0
a<5
a(,5)

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Quadratic Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon