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Question

Let S be the set of values of paramenter a for which the points of intersection of the parabolas y2=3ax and y=12(x2+ax+5) are concyclic, then S can be

A
(2,)
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B
(,2)
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C
(,2)
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D
(2,)
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Solution

The correct options are
C (,2)
D (2,)
Any curve througth intersection of given curves will be of form
y23ax+λ(x2+ax+52y)=0(1)
This should be a real circle λ=1 and radius >0
x2+y22ax2y+5=0(xa)2+(y1)2=a24
a24>0a>2 or a<2

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