Question

Let's find the value of $\angle AOP$ and $\angle BOP$ if the measurement of $\angle AOP$ is more than $\angle BOP$ by ${140}^o$

Answer 1

$\angle AOP=\angle BOP+{140}^{\circ }$

$\angle AOP+\angle BOP={180}^{\circ }$

$\angle BOP+{140}^{\circ }+\angle BOP={180}^{\circ }$

$2\angle BOP={40}^{\circ }$

$\angle BOP={20}^{\circ }$

$\angle AOP={160}^{\circ }$