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Byju's Answer
Standard XII
Mathematics
Inverse of a Function
Let S = a, ...
Question
Let
S
=
{
a
,
b
,
c
}
and
T
=
{
1
,
2
,
3
}
. Find
F
−
1
of the following functions
F
from
S
to
T
, if it exists
(i)
F
=
{
(
a
,
3
)
,
(
b
,
2
)
,
(
c
,
1
)
}
(ii)
F
=
{
(
a
,
2
)
,
(
b
,
1
)
,
(
c
,
1
)
}
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Solution
S
=
{
a
,
b
,
c
}
T
=
{
1
,
2
,
3
}
F
=
{
(
a
,
3
)
,
(
b
,
2
)
,
(
c
,
1
)
}
F
−
1
=
{
(
3
,
a
)
,
(
2
,
b
)
,
(
1
,
c
)
}
F
=
{
(
a
,
2
)
,
(
b
,
1
)
,
(
c
,
1
)
}
The function is not invertibe since it is not bijective.
Suggest Corrections
0
Similar questions
Q.
Consider f : {1, 2, 3} → { a , b , c } given by f (1) = a , f (2) = b and f (3) = c . Find f −1 and show that ( f −1 ) −1 = f .
Q.
Let
f
be a real valued function defined as
f
(
x
)
=
x
2
+
x
2
1
∫
−
1
t
⋅
f
(
t
)
d
t
+
x
3
1
∫
−
1
f
(
t
)
d
t
.
Then which of the following hold(s) good ?
Q.
Let
A
=
{
1
,
2
,
3
}
,
B
=
{
a
,
b
,
c
}
and If
f
=
{
(
1
,
a
)
,
(
2
,
b
)
,
(
3
,
c
)
}
,
g
=
{
(
1
,
b
)
,
(
2
,
a
)
,
(
3
,
b
)
}
,
h
=
{
(
1
,
b
)
(
2
,
c
)
,
(
3
,
a
)
}
then
Q.
If
cos
−
1
(
a
)
+
cos
−
1
(
b
)
+
cos
−
1
(
c
)
=
3
π
and
f
be a function such that
f
(
1
)
=
2
and
f
(
x
+
y
)
=
f
(
x
)
⋅
f
(
y
)
for all
x
,
y
∈
R
,
then the value of
a
2
f
(
1
)
+
b
2
f
(
2
)
+
c
2
f
(
3
)
+
a
+
b
+
c
a
2
f
(
1
)
+
b
2
f
(
2
)
+
c
2
f
(
3
)
is
Q.
Let f (x) =
A
x
2
+
B
x
+
C
where A,B,C, are real numbers Find A,B,C if
f
(
1
)
=
6
,
f
(
0
)
=
3
,
f
(
−
1
)
=
2
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