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Question

Let Sn denote the sum of n terms of an AP, if S2n=3Sn, then the ratio S3nSn is equal to

A
9
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B
6
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C
16
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D
12
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Solution

The correct option is C 6
Solution :-
we know Sn=n(n+1)2

Given S2n=3sn

2n(2n+1)2=3.n(n+1)2

4n+2=3n+3

n=1

then S3nSn=3n(3n+1)2÷n(n+1)2=3×42×1=6

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