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Question

Let Sn= nC0 nC1+ nC1 nC2+...+ nCn1 nCn.
If Sn+1Sn=154, then sum of all possible values of n(n ϵ N) is

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Solution

Sn= nC0 nC1+ nC1 nC2+...+ nCn1 nCn= 2nCn+1

Sn+1= 2n+2Cn+2

Sn+1Sn=2n+2Cn+22nCn+1=154

(2n+2)(2n+1)n(n+2)=154

n26n+8=0

n=2, 4

Sum =2+4=6

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