Let S1 be a square of side a. Another square S2 is formed by joining the mid-points of the sides of S1. The same process is applied to S2 to form yet another square S3, and so on. If A1, A2, A3, ……… be the areas and P1, P2, P3, ……… be the perimeters of S1, S2, S3, ……., respectively, then the ratio equals :(CAT 2003)
Option (c)
From the given condition in question
Area and perimeter of S1 = a2, 4a
Area and perimeter of S2 =
Area and perimeter of S3 =
Area and perimeter of S4
These are 2 infinite GPs , which can be solved as follows
Required ratio
=
=
= → →