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Question

Let σ21 be the variance of the dataset {1,4,7,10,,301} and σ22 be the variance of the dataset {7,13,19,25,,607}. Then the value of σ22σ21σ21 is 


Solution

S1={1,4,7,10,,301}
S2={7,13,19,25,,607}
Let nth term of S1 is denoted by Tn.
Then nth term of S2 will be denoted as 2Tn+5.

We know Var(aX+b)=a2Var(X)
So, σ22=22σ21=4σ21   
σ22σ21σ21=σ22σ211
               =4σ21σ211
               =41
               =3

Mathematics

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