Let tn represents the nth term of a G.P. If t3=2 and t6=−14, then the value of t10 is
A
−1128
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B
−164
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C
1128
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D
164
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Solution
The correct option is B−164 Given : t3=2,t6=−14
Let the first term and common ratio of the G.P. be a and r respectively, then ar2=2,ar5=−14
Dividing both, we get ⇒r3=−18⇒r=−12
Now, a×14=2⇒a=8
Therefore, the 10th term is t10=ar9⇒t10=8(−12)9=−164