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Question

Let tn represents the nth term of a G.P. If t3=2 and t6=14, then the value of t10 is

A
1128
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B
164
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C
1128
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D
164
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Solution

The correct option is B 164
Given : t3=2, t6=14
Let the first term and common ratio of the G.P. be a and r respectively, then
ar2=2, ar5=14
Dividing both, we get
r3=18r=12
Now,
a×14=2a=8
Therefore, the 10th term is
t10=ar9t10=8(12)9=164

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