Let Tr be the rth term of an A.P. for r∈N. If for some positive integers m and n, we have Tm=1n and Tn=1m, then Tmn is equal to
A
1mn
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B
1m+1n
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C
1
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D
0
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Solution
The correct option is C1 It is given that tm=1n and tn=1m i.e., a+(m−1)d=1n a+(n−1)d=1m Subtracting both, we get: (m−n)d=1n−1m Thus, d=1mn Substitute, d=1mn to get, a=1mn. Thus, tmn=a+(mn−1)d=1