Let T r be the rth term of an AP- for r -1-2- - If for some positive integers m - n- we have T m -1- n and T n -1- mthen T mn equalsA- 1B- 1-m-1-nC- 1D- 0

The correct option is C a + (m 1)d = 1/n a + (n 1)d = 1/m ⇒ T_mn = 1 ...

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Standard X

Mathematics

General Form of an AP

Let T r be th...

Question

Let $T_{r}$ be the rth term of an AP, for r = 1, 2, . . . . . If for some positive integers m, n, we have $T_{m} = \frac{1}{n} a n d T_{n} = \frac{1}{m}$
then $T_{m n}$ equals

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Solution

The correct option is C
$a + (m - 1) d = \frac{1}{n} a + (n - 1) d = \frac{1}{m} \Rightarrow T_{m n} = 1$

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Let Tr be the rth term of an AP, for r = 1, 2, . . . . . If for some positive integers m, n, we have Tm=1n and Tn=1m then Tmn equals

The correct option is C a+(m−1)d=1na+(n−1)d=1m⇒Tmn=1

Let $T_{r}$ be the rth term of an AP, for r = 1, 2, . . . . . If for some positive integers m, n, we have $T_{m} = \frac{1}{n} a n d T_{n} = \frac{1}{m}$
then $T_{m n}$ equals

The correct option is C
$a + (m - 1) d = \frac{1}{n} a + (n - 1) d = \frac{1}{m} \Rightarrow T_{m n} = 1$