Question

Let $\tan A=\frac{3}{4}$ and $\tan B=\frac{4}{3}$. Find the value of $A+B$.

Answer 1

Now, $\tan A=\frac{3}{4}$ and $\tan B=\frac{4}{3}$.

Now we have,

$\tan (A+B)=\frac{\tan A+\tan B}{1-\tan A.\tan B}$.

or, $\tan (A+B)=\frac{\frac{3}{4}+\frac{4}{3}}{1-1}$

or, $\tan (A+B)=\infty$

or, $A+B=\frac{\pi }{2}$.