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Question

Let tanα,tanβ and tanγ;α,β,γ[2n1]π/2,nN be the slopes of three-line segments OA,OBandOC, respectively, where O is the origin. If the circumcentre of the ABC coincides with the origin and its orthocentre lies on the y-axis, then the value of cos3α+cos3β+cos3γcosα.cosβ.cosγ2 is equal to


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Solution

Determine the value of cos3α+cos3β+cos3γcosα.cosβ.cosγ2

The circumcenter and orthocenter both lies on the y-axis. Therefore, centroid also lies on the y-axis

On solving, we get:

cosα=0cosα+cosβ+cosγ=0

We know that if a+b+c=0, then a3+b3+c3=3abc

cos3α+cos3β+cos3γcosα.cosβ.cosγ=4cos3α-3cosα+4cos3β-3cosβ+4cos3γ-3cosγcosα.cosβ.cosγ=4cos3α+cos3β+cos3γ-3cosα+cosβ+cosγcosα.cosβ.cosγ=43cosα.cosβ.cosγ-3(0)cosα.cosβ.cosγcos3α+cos3β+cos3γcosα.cosβ.cosγ=12cos3α+cos3β+cos3γcosα.cosβ.cosγ2=144

Therefore, the value of(cos3α+cos3β+cos3γcosα.cosβ.cosγ)2is144.


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