Let (+) tartaric acid has a specific rotation of + 11.1. Calculate the specific rotation of a mixture of 68% (+) tartaric acid and 32% (-) tartaric acid Report your answer to the closest integer.
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Solution
Enantiomeric excess =d−ld+l×100=68−3268+32×100=36% ∴ Optical rotation of this mixture =36100×(11.1∘)=4