wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let the acute angle bisector of the two planes x2y2z+1=0 and 2x3y6z+1=0 be the plane P. Then which of the following points lies on P?

A
(2,0,12)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(0,2,4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(4,0,2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(3,1,12)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (2,0,12)
P1x2y2z+1=0, P22x3y6z+1=0
Pair of bisectors be
x2y2z+13=±2x3y6z+17
As a1a2+b1b2+c1c2=1(2)+(2)(3)+(2)(6)>0

ve sign gives acute angle bisector
i.e., 7(x2y2z+1)=3(2x3y6z+1)
13x23y32z+10=0
Clearly (2,0,12) satisfy above plane.

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle Bisectors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon