Let the algebraic sum of the perpendicular distances from the points (2,0),(0,2) & (1,1) to a variable straight line be zero, then the line passes through a fixed point whose co-ordinates are
A
(1,1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(2,3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(35,35)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A(1,1) Let the variable straight line be ax+by+c=0 ...(1) where algebraic sum of perpendiculars from (2,0),(0,2) and (1,1) is zero
∴2a+0+c√a2+b2+0+2b+c√a2+b2+a+b+c√a2+b2=0
⇒3a+3b+3c=0⇒a+b+c=0 From equation (1) and (2) ax+by+c=0 always passes through a fixed point (1,1).